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Prativa Shukla
M.Phill in zoology
MOLECULAR BASIS OF INHERITANCE
THE DNA
Structure of polynucleotide chain
 Polynucleotides are the polymer of nucleotides. DNA and RNA are polynucleotides. A nucleotides has 3 components
:
 1. A nitrogenous base.
 2. A pentose sugar ( ribose in RNA and deoxyribose in DNA)
 3. A phosphate group.
 Nitrogenous bases are 2 types:
 PURINES : It includes Adenine (A) and Gunine (G).
 PYRIMIDINES : It includes cytosine (C), thymine (T) and Uracil (U). Thymine ( 5- methyl Uracil) present only in DNA
and Uracil only in RNA.
 A nitrogenous base is linkrd to the OH of 1’C pentose sugar through an N-glycosidic linkage to form nucleoside.
Nucleosides in RNA Nucleosides in DNA
Adenosine Deoxyadenosine
Guanosine Deoxyguanosine
Cytidine Deoxycytidine
Uridine Deoxythymidine
 A phosphate group is linked to OH of 5’ C of a nucleotide through phosphoester linkage to form
nucleotide (or deoxynucleotide).
 In RNA, each nucleotide has an additional OH group at 2’ C of the ribose.
 2 nucleotides are linked through 3’-5’ phosphodiester bond to form dinucleotide.
 When more nucleotides are linked, it forms polynucleotide.
Structure of the DNA
 Watson and Crick proposed double helix model of DNA.
 DNA is made of 2 polynucleotide chains coiled in a right-handed fashion. Its backbone is formed of
sugar and phosphates.
 The 2 chains have anti-parallel polarity, i.e one chain has the polarity 5’- 3’ and the other has 3’- 5’.
 The bases in 2 strands are paired through H-bonds forming base pairs (bp).
 A=T (2 hydrogen bonds)
 C=G ( 3 hydrogen bonds)
 Purine comes opposite to a pyrimidine. This generates uniform distance between
the 2 strands.

Chargaff’s rule
 In DNA the propotion of A is equal to T and the proportion of G is equal to C.
 A+G=T+C
 NOTE:
 A bacteriophage has 5386 nucleotide.
 E.coli has 4.6×106 bp
 Haploid content of human DNA is 3.3×109 bp
 Length of DNA = number pf base pairs × distance between two adjacent pairs.
 Number of base pair in human = 6.6 × 109
 Hence , the length of DNA = 6.6 × 109 × 0.34 × 10–9 = 2.2 m
 In E.coli, length of DNA = 1.36 mm ( 1.36 × 10-3 mm)
 Therefore the number of base pairs
 1.36 × 10-3 / 0.34 × 10–9
 = 4 X 106 bp
Packaging of DNA helix
 In prokaryotes ( E.g- E.coli), the DNA is not scattered throughout the cell. DNA is negatively charged. So
it is held with some positively charged proteins to form nucleoid.
 In eukaryotes, there is a set of positively charged, basic proteins called histones.
 Histones are rich in positively charged basic amino acid residues lysine and arginines.
 8 histones form histone octamer.
 Negatively charged DNA is wrapped around histone octamer to give nucleosome.
 A typical nucleosome contains 200 bp. Therefore, total number of nucleosomes in human
= 6.6×109/200 = 3.3 ×107
 Nucleosome constitute the repeating unit to form chromatin. Chromatin is the thread-like
stained bodies.
 Higher level packaging of chromatin requires non-histone chromosomal proteins.
 Chromatin has two form:
 Euchromatin : loosely packed and transcriptionally active region of chromatin. It stains light.
 Heterochromatin : densely packed and inactive region of chromatin. It stains dark.
The search for Genetic Material
1. Griffith’s experiment
 Frederick Griffith used mice and Streptococcus pneumonia.
 Streptococcus pneumonia has 2 strain:
 Smooth (s) strain (Virulent) : Has polysaccharide mucus coat. Cause pneumonia.
 Rough (R) strain (Non-virulent) : No mucus coat. Do not cause Pneumonia.
Experiment:
He concluded that some ‘transforming principle’ transferred from heat-killed S-strain to R-strain. It enable R-strain
to synthesize smooth polysaccharide coat and become virulent. This must be due to the transfer of genetic
material.
Biochemical transforming principle
 Oswald Avery, Colin Macleod and Maclyn Mccarty worked to determine the biochemical nature of ‘
transforming principle’ in Griffith’s experiment.
 They purified biochemical (protein,DNA,RNA etc) from heat killed S cells using suitable enzymes.
 They discovered that :
 Digestion of protein and RNA (using Proteases and Rnases) did not affect transformation. It means that the
transforming substance was not a protein or RNA.
 Digestion of DNA with Dnase inhibited transformation. It means that DNA caused transformation of R cells to S
cells. It proves that DNA was the transforming principle.
Hershey-chase experiment
 Hershey and chase grew some bacteriophage viruses on a medium containg radioactive phosphorus P32 and
some others on medium containing radioactive sulphur S35.
 VIRUSES GROWN IN P32 got radioactive DNA because only DNA contains phosphorus. Viruses grown in S35
got radioactive protein because protein contain Sulphur.
 These preparations were used separately to infect E.coli.
 After infection, the E.coli cells were gently agitated in a blender to remove the virus particles from the
bacteria.
 Then the culture was centrifuged to separate lighter virus particles from heavier bacterial cells.
 Bacteria infected with viruses having radioactive DNA were radioactive. i.e DNA had passed from the Virus to
bacteria. Bacteria infected with viruses having radioactive proteins were not radioactive. I,e protein did not
enter the bacteria from the viruses. This proves that DNA is the genetic material.
Hershey-chase experiment
Properties of Genetic Material (DNA v/s
RNA)
 A genetic material must have the following properties :
 Ability to generate its replica ( replication).
 Chemical and structural ability.
 Provide the mutation that are required for evolution.
 Ability to express as Mendelian Characters.
Reason for stability of DNA Reason for mutability of RNA
Double stranded Single stranded
Presence of thymine Presence of Uracil
Absence of 2’-OH in sugar Presence of 2’-OH in sugar.
Properties of Genetic Material (DNA v/s
RNA)
 RNA is unstable. So, RNA viruses (E.g. Q.B bacteriophage, Tobacco Mosaic Virus etc) mutate and
evolve faster.
 DNA strands are complementary. On heating, they separate. In appropriate conditions, they come
together. In Griffith’s experiment, some properties of DNA of the heat killed bacteria did not
destroy. It indicates the stability of DNA.
 For the storage of genetic information, DNA is better due to its stability. But for the transmission
of genetic information, RNA is better.
 RNA can directly code for the protein synthesis, hence can easily express the characters. DNA is
dependent on RNA for protein synthesis.
RNA World
 RNA was the first genetic material.
 It act as genetic material and catalyst.
 Essential life processes ( metabolism, translation, splicing etc) evolved arund RNA.
 DNA evolved from RNA for stability.
Central dogma
 It is proposed by Francis Crick. It states that the genetic information flows from DNA  RNA 
Protein.
 In some viruses, flow of information is in reverse direction (from RNA to DNA). It is called reverse
transcription.
DNA Replication
 Replication is the copying of DNA from parental DNA.
 KEY POINTS:
 DNA replication is semiconservative. Each strand in the double helix acts as a template for
synthesis of a new, complementary strand.
 New DNA is made by enzymes called DNA polymerases, which require a template and
a primer (starter) and synthesize DNA in the 5' to 3' direction.
 During DNA replication, one new strand (the leading strand) is made as a continuous
piece. The other (the lagging strand) is made in small pieces.
 DNA replication requires other enzymes in addition to DNA polymerase, including DNA
primase, DNA helicase, DNA ligase, and topoisomerase.
Messelson and Sthal’s experiment
 They grew E.coli in 15NH4​Cl medium as the only nitrogen source. As a result, N15 was incorporated into
newly synthesized DNA
 Heavy DNA can be distinguished from normal DNA (N14) by centrifugation in a cesium chloride density
gradient.
 E. coli cells from N15 medium were transferred to N14 medium. After one generation (i.e, after 20 min), they
isolated and centrifuged the DNA. Its density was intermediate between N15 DNA and N14 DNA. This show
that in newly formed DNA, one strand is old (N15 type) and one strand is new (N14 type). This confirms
semi-conservative replication.
 After II generation (i.e after 40 min), there was equal amount of hybrid DNA and light DNA.
The machinery and enzyme for replication
 The DNA replication starts at a point called origin
 A unit of replication with one origin is called a replicon.
 During replication, the 2 strand unwind and separate by breaking H-bonds in presence of an enzyme,
Helicase.
 Unwinding of the DNA molecule at a point forms a Y-shaped structure called replication fork.
The machinery and enzyme for replication
 The separated strands act as templates for the synthesis of new strands.
 DNA replicates in the 5’ 3’ direction.
Mutation
 Relationship between genes and DNA are best understood by mutation studies. Deletions and
rearrangements in a DNA may cause loss or gain of gene and so a function.
 Insertion or deletion of one or two bases changes the reading frame from the point of insertion
or deletion. It is called frame-shift insertion or deletion mutations.
 Insertion/deletion of three or its multiple bases insert or delete one or multiple codon. The
reading frame remains unaltered from that point onwards. Hence one or multiple amino acids
are inserted/deleted.
 It proves that codon is a triplet and is read contiguously.
T-RNA (The adapter molecules)
 Brings amino acids for protein synthesis and reads the genetic code.
 Francis Crick postulated presence of an adapter molecules that can read the code and to link with amino acids.
 t-RNA is called adapter molecules because it has an anticodon loop that has bases complementary to the codon.
 An amino acid acceptor end to which amino acid binds.
 There are no tRNA for stop codon
 Secondary (2-D) structure of tRNA looks like a clover-leaf.
 3-D structure looks like inverted ‘L’.
DNA fingerprinting
 It is the technique to identify the similarities and differences of the DNA fragments of 2
individuals.
 It is developed by Alec Jeffreys (1985).
 Basis of DNA fingerprints :-
 DNA carries some non-coding repetitive sequence.
 Repetitive DNA can be separated from bulk genomic DNA as different peaKS during density
gradient centrifugation.
 The bulk DNA forms a maor peak and the small peaks are called satellite DNA.
 A DNA sequence which is tandemly repeated in many copy numbers is called variable number
tandem repeats (VNTR). It belongs to mini-satellite DNA.
 In a person, copy number varies in each chromosome.
 The two alleles of a chromosome also contain different copy numbers of VNTR.
 VNTR is specific from person to person.
Step of DNA fingerprinting
 1. Isolation of DNA from any cells or blood stains, semen stains, saliva, hair roots, bone, skin, etc.
 2. Digestion of DNA by restriction endonucleases.
 3. Separation of DNA fragments by gel electrophoresis.
 4. Transferring (blotting) DNA fragments to synthetic membranes such as nitrocellulose or nylon.
 5. Hybridization using radioactive labelled VNTR probe.
 6. Detection of hybridized DNA by autoradiography.
 The autoradiogram gives an image in the form of dark and light bands. It is called DNA fingerprints.
 DNA fingerprints differs in everyone except in monozygotic (identical) twins.
 DNA from a single cell is enough for DNA fingerprinting.
 Dark and light bands
Application of DNA fingerprinting
 Forensic tools to solve paternity, rape, murder etc.
 For the diagnosis of genetic diseases.
 To determine phylogenetic status of animals.
 To determine population and genetic diversities.

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molecular basis of inheritance in files .pptx

  • 1. Prativa Shukla M.Phill in zoology MOLECULAR BASIS OF INHERITANCE
  • 2. THE DNA Structure of polynucleotide chain  Polynucleotides are the polymer of nucleotides. DNA and RNA are polynucleotides. A nucleotides has 3 components :  1. A nitrogenous base.  2. A pentose sugar ( ribose in RNA and deoxyribose in DNA)  3. A phosphate group.  Nitrogenous bases are 2 types:  PURINES : It includes Adenine (A) and Gunine (G).  PYRIMIDINES : It includes cytosine (C), thymine (T) and Uracil (U). Thymine ( 5- methyl Uracil) present only in DNA and Uracil only in RNA.  A nitrogenous base is linkrd to the OH of 1’C pentose sugar through an N-glycosidic linkage to form nucleoside.
  • 3. Nucleosides in RNA Nucleosides in DNA Adenosine Deoxyadenosine Guanosine Deoxyguanosine Cytidine Deoxycytidine Uridine Deoxythymidine
  • 4.  A phosphate group is linked to OH of 5’ C of a nucleotide through phosphoester linkage to form nucleotide (or deoxynucleotide).  In RNA, each nucleotide has an additional OH group at 2’ C of the ribose.  2 nucleotides are linked through 3’-5’ phosphodiester bond to form dinucleotide.  When more nucleotides are linked, it forms polynucleotide.
  • 5. Structure of the DNA  Watson and Crick proposed double helix model of DNA.  DNA is made of 2 polynucleotide chains coiled in a right-handed fashion. Its backbone is formed of sugar and phosphates.  The 2 chains have anti-parallel polarity, i.e one chain has the polarity 5’- 3’ and the other has 3’- 5’.
  • 6.  The bases in 2 strands are paired through H-bonds forming base pairs (bp).  A=T (2 hydrogen bonds)  C=G ( 3 hydrogen bonds)  Purine comes opposite to a pyrimidine. This generates uniform distance between the 2 strands. 
  • 7. Chargaff’s rule  In DNA the propotion of A is equal to T and the proportion of G is equal to C.  A+G=T+C  NOTE:  A bacteriophage has 5386 nucleotide.  E.coli has 4.6×106 bp  Haploid content of human DNA is 3.3×109 bp  Length of DNA = number pf base pairs × distance between two adjacent pairs.  Number of base pair in human = 6.6 × 109  Hence , the length of DNA = 6.6 × 109 × 0.34 × 10–9 = 2.2 m  In E.coli, length of DNA = 1.36 mm ( 1.36 × 10-3 mm)  Therefore the number of base pairs  1.36 × 10-3 / 0.34 × 10–9  = 4 X 106 bp
  • 8. Packaging of DNA helix  In prokaryotes ( E.g- E.coli), the DNA is not scattered throughout the cell. DNA is negatively charged. So it is held with some positively charged proteins to form nucleoid.  In eukaryotes, there is a set of positively charged, basic proteins called histones.  Histones are rich in positively charged basic amino acid residues lysine and arginines.  8 histones form histone octamer.  Negatively charged DNA is wrapped around histone octamer to give nucleosome.
  • 9.  A typical nucleosome contains 200 bp. Therefore, total number of nucleosomes in human = 6.6×109/200 = 3.3 ×107  Nucleosome constitute the repeating unit to form chromatin. Chromatin is the thread-like stained bodies.  Higher level packaging of chromatin requires non-histone chromosomal proteins.  Chromatin has two form:  Euchromatin : loosely packed and transcriptionally active region of chromatin. It stains light.  Heterochromatin : densely packed and inactive region of chromatin. It stains dark.
  • 10. The search for Genetic Material 1. Griffith’s experiment  Frederick Griffith used mice and Streptococcus pneumonia.  Streptococcus pneumonia has 2 strain:  Smooth (s) strain (Virulent) : Has polysaccharide mucus coat. Cause pneumonia.  Rough (R) strain (Non-virulent) : No mucus coat. Do not cause Pneumonia.
  • 11. Experiment: He concluded that some ‘transforming principle’ transferred from heat-killed S-strain to R-strain. It enable R-strain to synthesize smooth polysaccharide coat and become virulent. This must be due to the transfer of genetic material.
  • 12. Biochemical transforming principle  Oswald Avery, Colin Macleod and Maclyn Mccarty worked to determine the biochemical nature of ‘ transforming principle’ in Griffith’s experiment.  They purified biochemical (protein,DNA,RNA etc) from heat killed S cells using suitable enzymes.  They discovered that :  Digestion of protein and RNA (using Proteases and Rnases) did not affect transformation. It means that the transforming substance was not a protein or RNA.  Digestion of DNA with Dnase inhibited transformation. It means that DNA caused transformation of R cells to S cells. It proves that DNA was the transforming principle.
  • 13. Hershey-chase experiment  Hershey and chase grew some bacteriophage viruses on a medium containg radioactive phosphorus P32 and some others on medium containing radioactive sulphur S35.  VIRUSES GROWN IN P32 got radioactive DNA because only DNA contains phosphorus. Viruses grown in S35 got radioactive protein because protein contain Sulphur.  These preparations were used separately to infect E.coli.  After infection, the E.coli cells were gently agitated in a blender to remove the virus particles from the bacteria.  Then the culture was centrifuged to separate lighter virus particles from heavier bacterial cells.  Bacteria infected with viruses having radioactive DNA were radioactive. i.e DNA had passed from the Virus to bacteria. Bacteria infected with viruses having radioactive proteins were not radioactive. I,e protein did not enter the bacteria from the viruses. This proves that DNA is the genetic material.
  • 15. Properties of Genetic Material (DNA v/s RNA)  A genetic material must have the following properties :  Ability to generate its replica ( replication).  Chemical and structural ability.  Provide the mutation that are required for evolution.  Ability to express as Mendelian Characters. Reason for stability of DNA Reason for mutability of RNA Double stranded Single stranded Presence of thymine Presence of Uracil Absence of 2’-OH in sugar Presence of 2’-OH in sugar.
  • 16. Properties of Genetic Material (DNA v/s RNA)  RNA is unstable. So, RNA viruses (E.g. Q.B bacteriophage, Tobacco Mosaic Virus etc) mutate and evolve faster.  DNA strands are complementary. On heating, they separate. In appropriate conditions, they come together. In Griffith’s experiment, some properties of DNA of the heat killed bacteria did not destroy. It indicates the stability of DNA.  For the storage of genetic information, DNA is better due to its stability. But for the transmission of genetic information, RNA is better.  RNA can directly code for the protein synthesis, hence can easily express the characters. DNA is dependent on RNA for protein synthesis.
  • 17. RNA World  RNA was the first genetic material.  It act as genetic material and catalyst.  Essential life processes ( metabolism, translation, splicing etc) evolved arund RNA.  DNA evolved from RNA for stability.
  • 18. Central dogma  It is proposed by Francis Crick. It states that the genetic information flows from DNA  RNA  Protein.  In some viruses, flow of information is in reverse direction (from RNA to DNA). It is called reverse transcription.
  • 19. DNA Replication  Replication is the copying of DNA from parental DNA.  KEY POINTS:  DNA replication is semiconservative. Each strand in the double helix acts as a template for synthesis of a new, complementary strand.  New DNA is made by enzymes called DNA polymerases, which require a template and a primer (starter) and synthesize DNA in the 5' to 3' direction.  During DNA replication, one new strand (the leading strand) is made as a continuous piece. The other (the lagging strand) is made in small pieces.  DNA replication requires other enzymes in addition to DNA polymerase, including DNA primase, DNA helicase, DNA ligase, and topoisomerase.
  • 20. Messelson and Sthal’s experiment  They grew E.coli in 15NH4​Cl medium as the only nitrogen source. As a result, N15 was incorporated into newly synthesized DNA  Heavy DNA can be distinguished from normal DNA (N14) by centrifugation in a cesium chloride density gradient.  E. coli cells from N15 medium were transferred to N14 medium. After one generation (i.e, after 20 min), they isolated and centrifuged the DNA. Its density was intermediate between N15 DNA and N14 DNA. This show that in newly formed DNA, one strand is old (N15 type) and one strand is new (N14 type). This confirms semi-conservative replication.  After II generation (i.e after 40 min), there was equal amount of hybrid DNA and light DNA.
  • 21. The machinery and enzyme for replication  The DNA replication starts at a point called origin  A unit of replication with one origin is called a replicon.  During replication, the 2 strand unwind and separate by breaking H-bonds in presence of an enzyme, Helicase.  Unwinding of the DNA molecule at a point forms a Y-shaped structure called replication fork.
  • 22. The machinery and enzyme for replication  The separated strands act as templates for the synthesis of new strands.  DNA replicates in the 5’ 3’ direction.
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  • 27. Mutation  Relationship between genes and DNA are best understood by mutation studies. Deletions and rearrangements in a DNA may cause loss or gain of gene and so a function.  Insertion or deletion of one or two bases changes the reading frame from the point of insertion or deletion. It is called frame-shift insertion or deletion mutations.  Insertion/deletion of three or its multiple bases insert or delete one or multiple codon. The reading frame remains unaltered from that point onwards. Hence one or multiple amino acids are inserted/deleted.  It proves that codon is a triplet and is read contiguously.
  • 28. T-RNA (The adapter molecules)  Brings amino acids for protein synthesis and reads the genetic code.  Francis Crick postulated presence of an adapter molecules that can read the code and to link with amino acids.  t-RNA is called adapter molecules because it has an anticodon loop that has bases complementary to the codon.  An amino acid acceptor end to which amino acid binds.  There are no tRNA for stop codon  Secondary (2-D) structure of tRNA looks like a clover-leaf.  3-D structure looks like inverted ‘L’.
  • 29. DNA fingerprinting  It is the technique to identify the similarities and differences of the DNA fragments of 2 individuals.  It is developed by Alec Jeffreys (1985).  Basis of DNA fingerprints :-  DNA carries some non-coding repetitive sequence.  Repetitive DNA can be separated from bulk genomic DNA as different peaKS during density gradient centrifugation.  The bulk DNA forms a maor peak and the small peaks are called satellite DNA.  A DNA sequence which is tandemly repeated in many copy numbers is called variable number tandem repeats (VNTR). It belongs to mini-satellite DNA.  In a person, copy number varies in each chromosome.  The two alleles of a chromosome also contain different copy numbers of VNTR.  VNTR is specific from person to person.
  • 30. Step of DNA fingerprinting  1. Isolation of DNA from any cells or blood stains, semen stains, saliva, hair roots, bone, skin, etc.  2. Digestion of DNA by restriction endonucleases.  3. Separation of DNA fragments by gel electrophoresis.  4. Transferring (blotting) DNA fragments to synthetic membranes such as nitrocellulose or nylon.  5. Hybridization using radioactive labelled VNTR probe.  6. Detection of hybridized DNA by autoradiography.  The autoradiogram gives an image in the form of dark and light bands. It is called DNA fingerprints.  DNA fingerprints differs in everyone except in monozygotic (identical) twins.  DNA from a single cell is enough for DNA fingerprinting.
  • 31.  Dark and light bands
  • 32. Application of DNA fingerprinting  Forensic tools to solve paternity, rape, murder etc.  For the diagnosis of genetic diseases.  To determine phylogenetic status of animals.  To determine population and genetic diversities.