Working towards the 2D projection, of a 3D torus.

1. 1 of 3
Torus Equations SlideShare v2. 2023/06/23.
Sharon Liu.
The tangent to the point on the circle, where theta is 2 degrees, was found, by working out the gradient, formed by the
neighbouring two points, on the circle. Then, the coordinates, where theta was two degrees, was fed into y = mx + c, to
find c. Then, a line was plotted, from m (the gradient) and c (the intercept).

2. 2 of 3

3. 3 of 3
The coordinates on the circle, where the tangents are m = -1, were found by direct calculation, as a simple screen (3D
plane) was used.