3. A projectile is shot straight up from a height of
6m with an initial velocity of 80 m/s. Its height in
metres above the ground after t seconds is
2
given by the equation h = 6 + 80t - 5t . After
how mny seconds does the projectile reach its
maximum height, and what is this height?
5. Exercise 7 Question 2
Exercise 7 Question 12
Exercise 6 Question 12
Finish these at home if necessary.
Pre-test tomorrow
Test on Thursday
Next unit: Trigonometry!!