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Integrate:
Find the equation of a curve if

and the curve passes through (1,3)
The rate of change in pressure, p units, at a depth 
x cm from the surface of a liquid is given by
 p'(x) = 0.03 x2. If the pressure at the surface is 10 
units, find the pressure at a depth of 5 cm.

11.25 units
The growth rate of a city's population has been 
modelled by the equation:
where t is the time in years after 1995 and N is the 
population size. In the year 2000 the population 
numbered 32 000.What will the population be in 
2010?

76981
Definite Integrals
By the end of the lesson you will be able to:

• Calculate definite integrals.
• Apply properties of definite integrals.
• Understand the relationship between definite 
  integrals and area.
The definite integral
If f(x)  is a continous function in the interval [a,b], 
and F(x) is any antiderivative, then:

is called the definite integral
and it is equal to : F(b) ­ F(a)
upper limit

lower limit
From these examples we can see that the definite 
integral can be a positive number , a negative 
number or zero.
Let's consider our first example:
the function in this case is 

f(x) = x

Let's draw f(x) between 0 and 3.

In this case the value of the definite integral 
represents the area below the curve, between 0 
and 3.
Let's consider the second example

Draw the graph of y = x3 for , ­1≤x≤1

The value of the 
definite integral 
does not represent 
the area below the 
curve.

How can we do to calculate the shaded area?
Shaded area = 
Let's consider now the third example:

and the graph of y = 2x+1  for ­3≤x≤1

Again the value of the 
definite integral does 
not represent the area 
below the curve.

How can we calculate 
this area?
Conclusions:

• 

may be positive, negative or zero.

•   When  f(x) > 0 in [a , b ]   then 
represents the area under the curve y = f(x), above 
the x­axis in the interval [a , b ].
Properties of the definite integral

1.

2.

3.

where a≤c≤b
4.
k ∈ lR

5.
Calculate the area under the curve y=x2 betwen 
x=1 and x=3.
Calculate:

Calculate the area beneath the curve y =x (x ­ 1)
 from x= 0 to x =1

check graph first !
Find the area between  the curve  y = x2 + 4 x  and the x­ axis 
 from x = ­2    to    x = 0 .

check graph first !
Find the area between  the curve  y = x2 + 4 x  and the x­ axis 
 from x = ­2    to    x = 2 .
16

Check graph first !!
Use of GDC:

Menu Run:

  OPTN
CALC (F4)

(F4)

upper limit

function

lower limit
Menu Graph:
Y1 =x2
DRAW

GSOLV (F5)

(F3)
Enter the lower limit and press EXE

Enter  the upper limit and press EXE
Book page 405 Ex 13G : 
1a) 2a) and 4, 5, 6.
Page 411 Ex 13H: 1 to 5

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