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B.A. (LAW ) PART II
ECONOMICS (213)
ALGEBRA FOR ECONOMICS
LEARNING OBJECTIVES 1) Macroeconomic Issues 2) Inflation 3) Unemployment
4) Business Cycle 5) Exchange Rate 6) Balance of Payment.
EXPRESSIONS AND EQUATIONS
An equation says that two things are equal. It will have an equals sign "=" like this:
x + 2 = 6
That equation says: what is on the left (x + 2) is equal to what is on the right (6)
So an equation is like a “statement” which says "this equals that"
PARTS OF AN EQUATION
There are names for different parts of equation. Here we have an equation that
says 4x − 7 equals 5, and all its parts:
A Variable is a symbol for a number we don't know yet. It is usually a letter like x
or y.
A number on its own is called a Constant.
A Coefficient is a number used to multiply a variable (4x means 4 times x, so 4 is a
coefficient).
Sometimes a letter stands in for the number:
Example: ax2
+ bx + c
 x is a variable
 a and b are coefficients
 c is a constant
An Operator is a symbol (such as +, -, × etc) that shows an operation (i.e. we want
to do something with the values).
A Term is either a single number or a variable, or numbers and variables multiplied
together.
An Expression is a group of terms (the terms are separated by + or − signs)
So, now we can say things like "that expression has only two terms", or "the
second term is a constant", or even "are you sure the coefficient is really 4?"
Exponents
The exponent (such as the 2 in x2
) says how many
times to use the value in a multiplication.
Examples:
82
= 8 × 8 = 64
y3
= y × y × y
y2
z = y × y × z
Exponents make it easier to write and use many multiplications
Example: y4
z2
is easier than y × y × y × y × z × z, or even yyyyzz
Polynomial
Example of a Polynomial: 3x2
+ x - 2
A polynomial can have constants, variables and the exponents 0,1,2,3,...
But it never has division by a variable.
Polynomials can be of different kinds; Monomial, Binomial, Trinomial
There are special names for polynomials with 1, 2 or 3 terms:
SIMPLIFYING ALGEBRAIC EXPRESSIONS
By “simplifying” an algebraic expression, we mean writing it in the most compact
or efficient manner, without changing the value of the expression. This mainly
involves collecting like terms, which means that we add together anything that can
be added together. The rule here is that only like terms can be added together.
Like Terms
Like Terms are terms whose variables and their exponents (such as the 2 in x2
) are
the same.
In other words, terms those are "like" each other. (Note: the coefficients can be
different)
Example:
(1/3)xy2
-2xy2
6xy2
Are all like terms because the variables are all xy2
So like terms are those terms which contain the same powers of same variables.
They can have different coefficients, but that is the only difference.
Examples:
3x, x, and –2x are like terms.
2x2
, –5x2
, and x2
are like terms.
xy2
, 3y2
x, and 3xy2
are like terms.
xy2
and x2
y are NOT like terms, because the same variable is not raised to the same
power.
Combining Like terms
Combining like terms is permitted. For example,
3x2
+ 5x2
= (3 + 5)x2
= 8x2
What happened here is that the distributive law was used in reverse—we
“undistributed” a common factor of x2
from each term. The way to think about this
operation is that if you have three x-squared, and then you get five more x-
squareds, you will then have eight x-squared.
Example: x2
+ 2x + 3x2
+ 2 + 4x + 7
Starting with the highest power of x, we see that there are four x-squared in all
(1x2
+ 3x2
). Then we collect the first powers of x, and see that there are six of them
(2x + 4x). The only thing left is the constants 2 + 7 = 9. Putting this all together we
get
x2
+ 2x + 3x2
+ 2 + 4x + 7
= 4x2
+ 6x + 9
Example 3.7
3x + 14x + 7x = 24x
Example 3.8
45A − 32A = 13A
It is important to note that only terms that have exactly the same algebraic notation
can be added or subtracted in this way. For example, the terms x, y2 and xy are all
different and cannot be added together or subtracted from each other.
Example 3.9 Simplify the expression
5x2
+ 6xy − 32x + 3yx − x2
+ 4x
 Solution Adding/subtracting all the terms in x2
gives 4x2
.
 Adding/subtracting all the terms in x gives −28x.
 Adding/subtracting all the terms in xy gives 9xy. (Note that the terms in xy
and yx can be added together since xy = yx.)
 Putting all these terms together gives the simplified expression 4x2
− 28x +
9xy
In fact all the basic rules of arithmetic apply when algebraic symbols are used
instead of actual numbers. The difference is that the simplified expression will still
be in a format of algebraic terms.
Parentheses
Parentheses must be multiplied out before collecting like terms.
You cannot combine things in parentheses (or other grouping symbols) with things
outside the parentheses. Think of parentheses as opaque—the stuff inside the
parentheses can’t “see” the stuff outside the parentheses. If there is some factor
multiplying the parentheses, then the only way to get rid of the parentheses is to
multiply using the distributive law.
Example: 3x + 2(x – 4)
= 3x + 2x – 8
= 5x – 8
Minus Signs: Subtraction and Negatives
Subtraction can be replaced by adding the opposite
3x – 2 = 3x + (–2)
Negative signs in front of parentheses
A special case is when a minus sign appears in front of parentheses. At first glance,
it looks as though there is no factor multiplying the parentheses, and you may be
tempted to just remove the parentheses. What you need to remember is that the
minus sign indicating subtraction should always be thought of as adding the
opposite. This means that you want to add the opposite of the entire thing inside
the parentheses, and so you have to change the sign of each term in the
parentheses. Another way of looking at it is to imagine an implied factor of one in
front of the parentheses. Then the minus sign makes that factor into a negative one,
which can be multiplied by the distributive law:
3x – (2 – x)
= 3x + (–1)[2 + (–x)]
= 3x + (–1)(2) + (–1)(–x)
= 3x – 2 + x
= 4x – 2
However, if there is only a plus sign in front of the parentheses, then you can
simply erase the parentheses:
3x + (2 – x)
= 3x + 2 – x
A comment about subtraction and minus signs
Although you can always explicitly replace subtraction with adding the opposite,
as in this previous example, it is often tedious and inconvenient to do so. Once you
get used to thinking that way, it is no longer necessary to actually write it that way.
It is helpful to always think of minus signs as being “stuck” to the term directly to
their right. That way, as you rearrange terms, collect like terms, and clear
parentheses, the “adding the opposite” business will be taken care of because the
minus signs will go with whatever was to their right. If what is immediately to the
right of a minus sign happens to be a parenthesis, then the minus sign attacks every
term inside the parentheses.
The example below illustrates the rule that if there is a negative sign in front of a
set of brackets then the positive and negative signs of the terms within the brackets
are reversed if the brackets are removed.
Example 3.10 Simplify the expression
16q + 33q − 2q − (15q − 6q)
Solution Removing brackets, the above expression becomes
16q + 33q − 2q − 15q + 6q = 38q
SOLUTIONS OF ALGEBRAIC EQUATIONS
Up until now, we have just been talking about manipulating algebraic expressions.
Now it is time to talk about equations. An expression is just a statement like 2x + 3
This expression might be equal to any number, depending on the choice of x. For
example, if x = 3 then the value of this expression is 9. But if we are writing an
equation, then we are making a statement about its value. We might say
2x + 3 = 7
A mathematical equation is either true or false. This equation, 2x + 3 = 7, might be
true or it might be false; it depends on the value chosen for x. We call such
equations conditional, because their truth depends on choosing the correct value
for x.
If we choose x = 3, then the equation is clearly false because 2(3) + 3 = 9, not 7. In
fact, it is only true if I choose x = 2. Any other value for x produces a false
equation. We say that x = 2 is the solution of this equation.
The solution of an equation is the value(s) of the variable(s) that make the equation
a true statement.
An equation like 2x + 3 = 7 is a simple type called a linear equation in one
variable. These will always have one solution, no solutions, or an infinite number
of solutions. There are other types of equations, however, that can have several
solutions. For example, the equation
x2
= 9
is satisfied by both 3 and –3, and so it has two solutions.
One Solution
This is the normal case, as in our example where the equation 2x + 3 = 7 had
exactly one solution, namely x = 2. The other two cases, no solution and an infinite
number of solutions, are the oddball cases that you don’t expect to run into very
often. Nevertheless, it is important to know that they can happen in case you do
encounter one of these situations.
Infinite Number of Solutions
Consider the equation
x = x
This equation is obviously true for every possible value of x. This is, of course, a
ridiculously simple example, but it makes the point. Equations that have this
property are called identities. Some examples of identities would be
2x = x + x
3 = 3
(x – 2)(x + 2) = x2
– 4
All of these equations are true for any value of x. The second example,
3 = 3, is interesting because it does not even contain an x, so obviously its
truthfulness cannot depend on the value of x! When you are attempting to
solve an equation algebraically and you end up with an obvious identity (like
3 = 3), then you know that the original equation must also be an identity, and
therefore it has an infinite number of solutions.
No Solutions
Now consider the equation
x + 4 = x + 3
There is no possible value for x that could make this true. If you take a number and
add 4 to it, it will never be the same as if you take the same number and add 3 to it.
Such an equation is called a contradiction, because it cannot ever be true.
ADDITION AND MULTIPLICATION PRINCIPLE
Equivalent Equations
The basic approach to finding the solution to equations is to change the equation
into simpler equations, but in such a way that the solution set of the new equation
is the same as the solution set of the original equation. When two equations have
the same solution set, we say that they are equivalent.
What we want to do when we solve an equation is to produce an equivalent
equation that tells us the solution directly. Going back to our previous example,
2x + 3 = 7,
we can say that the equation
x = 2
is an equivalent equation, because they both have the same solution, namely x = 2.
We need to have some way to convert an equation like 2x + 3 = 7 into an
equivalent equation like x = 2 that tells us the solution. We solve equations by
using methods that rearrange the equation in a manner that does not change the
solution set, with a goal of getting the variable by itself on one side of the equal
sign. Then the solution is just the number that appears on the other side of the
equal sign.
The methods of changing an equation without changing its solution set are based
on the idea that if you change both sides of an equation in the same way, then the
equality is preserved. Think of an equation as a balance—whatever complicated
expression might appear on either side of the equation, they are really just
numbers. The equal sign is just saying that the value of the expression on the left
side is the same number as the value on the right side. Therefore, no matter how
horrible the equation may seem, it is really just saying something like 3 = 3.
The Addition Principle
Adding (or subtracting) the same number to both sides of an equation does not
change its solution set.
Think of the balance analogy—if both sides of the equation are equal, then
increasing both sides by the same amount will change the value of each side, but
they will still be equal. For example, if
3 = 3,
then
3 + 2 = 3 + 2
Consequently, if
6 + x = 8
for some value of x (which in this case is x = 2), then we can add any
number to both sides of the equation and x = 2 will still be the solution. If we
wanted to, we could add a 3 to both sides of the equation, producing the
equation
9 + x = 11.
As you can see, x = 2 is still the solution. Of course, this new equation is no
simpler than the one we started with, and this maneuver did not help us solve
the equation.
If we want to solve the equation
6 + x = 8
the idea is to get x by itself on one side, and so we want to get rid of the 6
that is on the left side. We can do this by subtracting a 6 from both sides of
the equation (which of course can be thought of as adding a negative six):
6 – 6 + x = 8 – 6
or
x = 2
You can think of this operation as moving the 6 from one side of the
equation to the other, which causes it to change sign
The addition principle is useful in solving equations because it allows us to move
whole terms from one side of the equal sign to the other. While this is a convenient
way to think of it, you should remember that you are not really “moving” the term
from one side to the other—you are really adding (or subtracting) the term on both
sides of the equation.
Notation notes
In the previous example, we wrote the –6 in-line with the rest of the
equation. This is analogous to writing an arithmetic subtraction problem in
one line, as in
234 – 56 = 178.
You probably also learned to write subtraction and addition problems in a
column format, like
234
−56
178
We can also use a similar notation for the addition method with algebraic
equations.
Given the equation
x + 3 = 2,
We want to subtract a 3 from both sides in order to isolate the variable. In column
format this would look like
+ 3 = 2
−3 = −3
= −1
Here the numbers in the second row are negative 3’s, so we are adding the
two rows together to produce the bottom row.
The advantage of the column notation is that it makes the operation easier to
see and reduces the chances for an error. The disadvantage is that it takes
more space, but that is a relatively minor disadvantage. Which notation you
prefer to use is not important, as long as you can follow what you are doing
and it makes sense to you.
Multiplication Principle
Multiplying (or dividing) the same non-zero number to both sides of an
equation does not change its solution set.
Example:
6 2 = 12
3 6 2 = 3 12
so if 6x = 12, then 18x = 36 for the same value of x (which in this case
is x = 2).
The way we use the multiplication principle to solve equations is that it allows us
to isolate the variable by getting rid of a factor that is multiplying the variable.
Example: 2x = 6
To get rid of the 2 that is multiplying the x, we can divide both sides of the
equation by 2, or multiply by its reciprocal (one-half),
2X = 6
2
2
=
6
2
,
X = 3
or multiply both sides by a half:
2X = 6
1
2
2 =
1
2
6 ,
X = 3
Whether you prefer to think of it as dividing by the number or multiplying
by its reciprocal is not important, although when the coefficient is a fraction
it is easier to multiply by the reciprocal:
Example:
Multiply both sides by the reciprocal of the coefficient, or 5
4
Using the Principles Together
Suppose you were given an equation like 2x – 3 = 5.
You will need to use the addition principle to move the –3, and the
multiplication principle to remove the coefficient 2. Which one should you
use first? Strictly speaking, it does not matter—you will eventually get the
right answer. In practice, however, it is usually simpler to use the addition
principle first, and then the multiplication principle. The reason for this is
that if we divide by 2 first we will turn everything into fractions:
Given: 2x – 3 = 5
Suppose we first divide both sides by 2:
Now there is nothing wrong with doing arithmetic with fractions, but it is
not as simple as working with whole numbers. In this example we would
have to add 3/2 to both sides of the equation to isolate the x. It is usually
more convenient, though, to use the addition principle first:
Given: 2x – 3 = 5
Add 3 to both sides:
At this point all we need to do is divide both sides by 2 to get x = 4.
Assignment # 1, Simplify each expression by combining like terms.
S/N Question Answer
1 5r - 7 - 1 - 3r + r + 4r + 9 + 6 - 2r 5r + 7
2 -9p + 3 + 4p + 7p - 4p - 4p -6p + 3
3 8p - 3 + 9p + 6p + 2p - 6p - 3p - 9p 7p - 3
4 -6c + 2c - 4c + 2 - 4c + 6c - 1 - 3 + 5c -c - 2
5 -9v - 9 - 5v - 5 - v + 2 - 8 - 9 + 7v + 5v -3v - 29
6 -g - 4 - 5 - 9 + 5g + 7 - 9 + g - 9g -4g - 20
7 3 + 8 - 3z - 5 - 9z - 1 - 6 – 4 -12z - 5
8 -9m - 8 - 3m + 8m - 7m + 4 + 3 + 4 – m -12m + 3
9 3p - 3p + 3p + p + 7p + 7 - 4 - 3 - 3p - 7p p
10 9c + 9 + 2 - 8c + 6c - 5c – 9 2c + 2 M
Assignment # 2, Simplify each expression by combining like terms.
S/N Question Answer
1 -3(6v - 6) - 5(-8v + 3) 22v + 3
2. 3(3m - 1) + 5(6m + 7) 39m + 32
3. -4(-4m - 1) - 4(7m + 3) -12m - 8
4. (-3q + 3) + 7(8q + 1) 53q + 10
5. -7(-4b - 9) + 9(3b + 3) 55b + 90
6. -3(2) - 6(p + 8) -6p - 54
7. 6(9c - 4) + 9(c - 1) 63c - 33
8. 3(2c + 1) + 2(9c - 1) 24c + 1
9. -9(-4n + 3) - 3(5n + 6) 21n - 45
10. 5(9d - 2) + 6(5d - 2) 75d - 22
Assignment # 3, Solve for each variable..
S/N Question Answer
1 3b+9 = −18 b = −9
2 3v+1 = 22 v = 7
3 3y−2 = 10 y = 4
4 2z+1 = 15 z = 7
5. −2b−(−7) = 11 b = −2
6. 3c−9 = −27 c = −6
7. −3c−4 = 2 c = −2
8. −3c+8 = −10 c = 6
9. 2c−8 = −18 c = −5
10. 3a−5 = −23 a = −6
11. −2a−8 = −4 a = −2
12. 3z−2 = −26 z = −8
13. 2u+7 = 5 u = −1
14. 3a−(−1) = −5 a = −2
15. −2u+ (−1) = −13 u = 6
Solve the following three questions to find the value of variable.
Equation Answer
8
= −4, ( = −32)
b – (-5) = 13 (b = 8)
8
− (
−2) = 6 ( = 2)

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ALGEBRA FOR ECONOMICS EXPRESSIONS AND EQUATIONS

  • 1. B.A. (LAW ) PART II ECONOMICS (213) ALGEBRA FOR ECONOMICS LEARNING OBJECTIVES 1) Macroeconomic Issues 2) Inflation 3) Unemployment 4) Business Cycle 5) Exchange Rate 6) Balance of Payment. EXPRESSIONS AND EQUATIONS An equation says that two things are equal. It will have an equals sign "=" like this: x + 2 = 6 That equation says: what is on the left (x + 2) is equal to what is on the right (6) So an equation is like a “statement” which says "this equals that" PARTS OF AN EQUATION There are names for different parts of equation. Here we have an equation that says 4x − 7 equals 5, and all its parts: A Variable is a symbol for a number we don't know yet. It is usually a letter like x or y.
  • 2. A number on its own is called a Constant. A Coefficient is a number used to multiply a variable (4x means 4 times x, so 4 is a coefficient). Sometimes a letter stands in for the number: Example: ax2 + bx + c  x is a variable  a and b are coefficients  c is a constant An Operator is a symbol (such as +, -, × etc) that shows an operation (i.e. we want to do something with the values). A Term is either a single number or a variable, or numbers and variables multiplied together. An Expression is a group of terms (the terms are separated by + or − signs) So, now we can say things like "that expression has only two terms", or "the second term is a constant", or even "are you sure the coefficient is really 4?"
  • 3. Exponents The exponent (such as the 2 in x2 ) says how many times to use the value in a multiplication. Examples: 82 = 8 × 8 = 64 y3 = y × y × y y2 z = y × y × z Exponents make it easier to write and use many multiplications Example: y4 z2 is easier than y × y × y × y × z × z, or even yyyyzz Polynomial Example of a Polynomial: 3x2 + x - 2 A polynomial can have constants, variables and the exponents 0,1,2,3,...
  • 4. But it never has division by a variable. Polynomials can be of different kinds; Monomial, Binomial, Trinomial There are special names for polynomials with 1, 2 or 3 terms: SIMPLIFYING ALGEBRAIC EXPRESSIONS By “simplifying” an algebraic expression, we mean writing it in the most compact or efficient manner, without changing the value of the expression. This mainly involves collecting like terms, which means that we add together anything that can be added together. The rule here is that only like terms can be added together. Like Terms Like Terms are terms whose variables and their exponents (such as the 2 in x2 ) are the same. In other words, terms those are "like" each other. (Note: the coefficients can be different) Example: (1/3)xy2 -2xy2 6xy2 Are all like terms because the variables are all xy2
  • 5. So like terms are those terms which contain the same powers of same variables. They can have different coefficients, but that is the only difference. Examples: 3x, x, and –2x are like terms. 2x2 , –5x2 , and x2 are like terms. xy2 , 3y2 x, and 3xy2 are like terms. xy2 and x2 y are NOT like terms, because the same variable is not raised to the same power. Combining Like terms Combining like terms is permitted. For example, 3x2 + 5x2 = (3 + 5)x2 = 8x2 What happened here is that the distributive law was used in reverse—we “undistributed” a common factor of x2 from each term. The way to think about this operation is that if you have three x-squared, and then you get five more x- squareds, you will then have eight x-squared. Example: x2 + 2x + 3x2 + 2 + 4x + 7 Starting with the highest power of x, we see that there are four x-squared in all (1x2 + 3x2 ). Then we collect the first powers of x, and see that there are six of them (2x + 4x). The only thing left is the constants 2 + 7 = 9. Putting this all together we get
  • 6. x2 + 2x + 3x2 + 2 + 4x + 7 = 4x2 + 6x + 9 Example 3.7 3x + 14x + 7x = 24x Example 3.8 45A − 32A = 13A It is important to note that only terms that have exactly the same algebraic notation can be added or subtracted in this way. For example, the terms x, y2 and xy are all different and cannot be added together or subtracted from each other. Example 3.9 Simplify the expression 5x2 + 6xy − 32x + 3yx − x2 + 4x  Solution Adding/subtracting all the terms in x2 gives 4x2 .  Adding/subtracting all the terms in x gives −28x.  Adding/subtracting all the terms in xy gives 9xy. (Note that the terms in xy and yx can be added together since xy = yx.)  Putting all these terms together gives the simplified expression 4x2 − 28x + 9xy In fact all the basic rules of arithmetic apply when algebraic symbols are used instead of actual numbers. The difference is that the simplified expression will still be in a format of algebraic terms.
  • 7. Parentheses Parentheses must be multiplied out before collecting like terms. You cannot combine things in parentheses (or other grouping symbols) with things outside the parentheses. Think of parentheses as opaque—the stuff inside the parentheses can’t “see” the stuff outside the parentheses. If there is some factor multiplying the parentheses, then the only way to get rid of the parentheses is to multiply using the distributive law. Example: 3x + 2(x – 4) = 3x + 2x – 8 = 5x – 8 Minus Signs: Subtraction and Negatives Subtraction can be replaced by adding the opposite 3x – 2 = 3x + (–2) Negative signs in front of parentheses A special case is when a minus sign appears in front of parentheses. At first glance, it looks as though there is no factor multiplying the parentheses, and you may be tempted to just remove the parentheses. What you need to remember is that the minus sign indicating subtraction should always be thought of as adding the opposite. This means that you want to add the opposite of the entire thing inside the parentheses, and so you have to change the sign of each term in the parentheses. Another way of looking at it is to imagine an implied factor of one in
  • 8. front of the parentheses. Then the minus sign makes that factor into a negative one, which can be multiplied by the distributive law: 3x – (2 – x) = 3x + (–1)[2 + (–x)] = 3x + (–1)(2) + (–1)(–x) = 3x – 2 + x = 4x – 2 However, if there is only a plus sign in front of the parentheses, then you can simply erase the parentheses: 3x + (2 – x) = 3x + 2 – x A comment about subtraction and minus signs Although you can always explicitly replace subtraction with adding the opposite, as in this previous example, it is often tedious and inconvenient to do so. Once you get used to thinking that way, it is no longer necessary to actually write it that way. It is helpful to always think of minus signs as being “stuck” to the term directly to their right. That way, as you rearrange terms, collect like terms, and clear parentheses, the “adding the opposite” business will be taken care of because the minus signs will go with whatever was to their right. If what is immediately to the right of a minus sign happens to be a parenthesis, then the minus sign attacks every term inside the parentheses.
  • 9. The example below illustrates the rule that if there is a negative sign in front of a set of brackets then the positive and negative signs of the terms within the brackets are reversed if the brackets are removed. Example 3.10 Simplify the expression 16q + 33q − 2q − (15q − 6q) Solution Removing brackets, the above expression becomes 16q + 33q − 2q − 15q + 6q = 38q SOLUTIONS OF ALGEBRAIC EQUATIONS Up until now, we have just been talking about manipulating algebraic expressions. Now it is time to talk about equations. An expression is just a statement like 2x + 3 This expression might be equal to any number, depending on the choice of x. For example, if x = 3 then the value of this expression is 9. But if we are writing an equation, then we are making a statement about its value. We might say 2x + 3 = 7 A mathematical equation is either true or false. This equation, 2x + 3 = 7, might be true or it might be false; it depends on the value chosen for x. We call such equations conditional, because their truth depends on choosing the correct value for x.
  • 10. If we choose x = 3, then the equation is clearly false because 2(3) + 3 = 9, not 7. In fact, it is only true if I choose x = 2. Any other value for x produces a false equation. We say that x = 2 is the solution of this equation. The solution of an equation is the value(s) of the variable(s) that make the equation a true statement. An equation like 2x + 3 = 7 is a simple type called a linear equation in one variable. These will always have one solution, no solutions, or an infinite number of solutions. There are other types of equations, however, that can have several solutions. For example, the equation x2 = 9 is satisfied by both 3 and –3, and so it has two solutions. One Solution This is the normal case, as in our example where the equation 2x + 3 = 7 had exactly one solution, namely x = 2. The other two cases, no solution and an infinite number of solutions, are the oddball cases that you don’t expect to run into very often. Nevertheless, it is important to know that they can happen in case you do encounter one of these situations. Infinite Number of Solutions Consider the equation x = x
  • 11. This equation is obviously true for every possible value of x. This is, of course, a ridiculously simple example, but it makes the point. Equations that have this property are called identities. Some examples of identities would be 2x = x + x 3 = 3 (x – 2)(x + 2) = x2 – 4 All of these equations are true for any value of x. The second example, 3 = 3, is interesting because it does not even contain an x, so obviously its truthfulness cannot depend on the value of x! When you are attempting to solve an equation algebraically and you end up with an obvious identity (like 3 = 3), then you know that the original equation must also be an identity, and therefore it has an infinite number of solutions. No Solutions Now consider the equation x + 4 = x + 3 There is no possible value for x that could make this true. If you take a number and add 4 to it, it will never be the same as if you take the same number and add 3 to it. Such an equation is called a contradiction, because it cannot ever be true.
  • 12. ADDITION AND MULTIPLICATION PRINCIPLE Equivalent Equations The basic approach to finding the solution to equations is to change the equation into simpler equations, but in such a way that the solution set of the new equation is the same as the solution set of the original equation. When two equations have the same solution set, we say that they are equivalent. What we want to do when we solve an equation is to produce an equivalent equation that tells us the solution directly. Going back to our previous example, 2x + 3 = 7, we can say that the equation x = 2 is an equivalent equation, because they both have the same solution, namely x = 2. We need to have some way to convert an equation like 2x + 3 = 7 into an equivalent equation like x = 2 that tells us the solution. We solve equations by using methods that rearrange the equation in a manner that does not change the solution set, with a goal of getting the variable by itself on one side of the equal sign. Then the solution is just the number that appears on the other side of the equal sign. The methods of changing an equation without changing its solution set are based on the idea that if you change both sides of an equation in the same way, then the equality is preserved. Think of an equation as a balance—whatever complicated expression might appear on either side of the equation, they are really just
  • 13. numbers. The equal sign is just saying that the value of the expression on the left side is the same number as the value on the right side. Therefore, no matter how horrible the equation may seem, it is really just saying something like 3 = 3. The Addition Principle Adding (or subtracting) the same number to both sides of an equation does not change its solution set. Think of the balance analogy—if both sides of the equation are equal, then increasing both sides by the same amount will change the value of each side, but they will still be equal. For example, if 3 = 3, then 3 + 2 = 3 + 2 Consequently, if 6 + x = 8 for some value of x (which in this case is x = 2), then we can add any number to both sides of the equation and x = 2 will still be the solution. If we wanted to, we could add a 3 to both sides of the equation, producing the equation 9 + x = 11.
  • 14. As you can see, x = 2 is still the solution. Of course, this new equation is no simpler than the one we started with, and this maneuver did not help us solve the equation. If we want to solve the equation 6 + x = 8 the idea is to get x by itself on one side, and so we want to get rid of the 6 that is on the left side. We can do this by subtracting a 6 from both sides of the equation (which of course can be thought of as adding a negative six): 6 – 6 + x = 8 – 6 or x = 2 You can think of this operation as moving the 6 from one side of the equation to the other, which causes it to change sign The addition principle is useful in solving equations because it allows us to move whole terms from one side of the equal sign to the other. While this is a convenient way to think of it, you should remember that you are not really “moving” the term from one side to the other—you are really adding (or subtracting) the term on both sides of the equation.
  • 15. Notation notes In the previous example, we wrote the –6 in-line with the rest of the equation. This is analogous to writing an arithmetic subtraction problem in one line, as in 234 – 56 = 178. You probably also learned to write subtraction and addition problems in a column format, like 234 −56 178 We can also use a similar notation for the addition method with algebraic equations. Given the equation x + 3 = 2, We want to subtract a 3 from both sides in order to isolate the variable. In column format this would look like + 3 = 2 −3 = −3 = −1 Here the numbers in the second row are negative 3’s, so we are adding the two rows together to produce the bottom row.
  • 16. The advantage of the column notation is that it makes the operation easier to see and reduces the chances for an error. The disadvantage is that it takes more space, but that is a relatively minor disadvantage. Which notation you prefer to use is not important, as long as you can follow what you are doing and it makes sense to you. Multiplication Principle Multiplying (or dividing) the same non-zero number to both sides of an equation does not change its solution set. Example: 6 2 = 12 3 6 2 = 3 12 so if 6x = 12, then 18x = 36 for the same value of x (which in this case is x = 2). The way we use the multiplication principle to solve equations is that it allows us to isolate the variable by getting rid of a factor that is multiplying the variable. Example: 2x = 6 To get rid of the 2 that is multiplying the x, we can divide both sides of the equation by 2, or multiply by its reciprocal (one-half), 2X = 6 2 2 = 6 2 , X = 3
  • 17. or multiply both sides by a half: 2X = 6 1 2 2 = 1 2 6 , X = 3 Whether you prefer to think of it as dividing by the number or multiplying by its reciprocal is not important, although when the coefficient is a fraction it is easier to multiply by the reciprocal: Example: Multiply both sides by the reciprocal of the coefficient, or 5 4 Using the Principles Together Suppose you were given an equation like 2x – 3 = 5. You will need to use the addition principle to move the –3, and the multiplication principle to remove the coefficient 2. Which one should you use first? Strictly speaking, it does not matter—you will eventually get the right answer. In practice, however, it is usually simpler to use the addition
  • 18. principle first, and then the multiplication principle. The reason for this is that if we divide by 2 first we will turn everything into fractions: Given: 2x – 3 = 5 Suppose we first divide both sides by 2: Now there is nothing wrong with doing arithmetic with fractions, but it is not as simple as working with whole numbers. In this example we would have to add 3/2 to both sides of the equation to isolate the x. It is usually more convenient, though, to use the addition principle first: Given: 2x – 3 = 5 Add 3 to both sides: At this point all we need to do is divide both sides by 2 to get x = 4.
  • 19. Assignment # 1, Simplify each expression by combining like terms. S/N Question Answer 1 5r - 7 - 1 - 3r + r + 4r + 9 + 6 - 2r 5r + 7 2 -9p + 3 + 4p + 7p - 4p - 4p -6p + 3 3 8p - 3 + 9p + 6p + 2p - 6p - 3p - 9p 7p - 3 4 -6c + 2c - 4c + 2 - 4c + 6c - 1 - 3 + 5c -c - 2 5 -9v - 9 - 5v - 5 - v + 2 - 8 - 9 + 7v + 5v -3v - 29 6 -g - 4 - 5 - 9 + 5g + 7 - 9 + g - 9g -4g - 20 7 3 + 8 - 3z - 5 - 9z - 1 - 6 – 4 -12z - 5 8 -9m - 8 - 3m + 8m - 7m + 4 + 3 + 4 – m -12m + 3 9 3p - 3p + 3p + p + 7p + 7 - 4 - 3 - 3p - 7p p 10 9c + 9 + 2 - 8c + 6c - 5c – 9 2c + 2 M Assignment # 2, Simplify each expression by combining like terms. S/N Question Answer 1 -3(6v - 6) - 5(-8v + 3) 22v + 3 2. 3(3m - 1) + 5(6m + 7) 39m + 32 3. -4(-4m - 1) - 4(7m + 3) -12m - 8 4. (-3q + 3) + 7(8q + 1) 53q + 10 5. -7(-4b - 9) + 9(3b + 3) 55b + 90 6. -3(2) - 6(p + 8) -6p - 54 7. 6(9c - 4) + 9(c - 1) 63c - 33 8. 3(2c + 1) + 2(9c - 1) 24c + 1 9. -9(-4n + 3) - 3(5n + 6) 21n - 45 10. 5(9d - 2) + 6(5d - 2) 75d - 22
  • 20. Assignment # 3, Solve for each variable.. S/N Question Answer 1 3b+9 = −18 b = −9 2 3v+1 = 22 v = 7 3 3y−2 = 10 y = 4 4 2z+1 = 15 z = 7 5. −2b−(−7) = 11 b = −2 6. 3c−9 = −27 c = −6 7. −3c−4 = 2 c = −2 8. −3c+8 = −10 c = 6 9. 2c−8 = −18 c = −5 10. 3a−5 = −23 a = −6 11. −2a−8 = −4 a = −2 12. 3z−2 = −26 z = −8 13. 2u+7 = 5 u = −1 14. 3a−(−1) = −5 a = −2 15. −2u+ (−1) = −13 u = 6 Solve the following three questions to find the value of variable. Equation Answer 8 = −4, ( = −32) b – (-5) = 13 (b = 8) 8 − ( −2) = 6 ( = 2)