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Antiderivatives
5.1
Discovery of Power Rule for
Antiderivatives
If f ‘ (x) =
Then f(x) =
If f ‘ (x) =
Then f(x) =
If f ‘ (x) =
Then f(x) =
If f ‘ (x) =
Then f(x) =
3
2
9
4 2
3


 x
x
x
x
x
x
x 3
3 2
3
4



2
3 
 x
x
x
x
x 2
2
3
3
2 2
2
3


5
4
3
2
3 2


 x
x
x
x
x
x
x 5
2
2
3
5
3 2
2
3
5


 
5
3
4 2


 x
x
x
x
x 5
2
3
3
4 2
3



1
of
tive
Antideriva
1



n
x
x
n
n
Differentiation
Integration
The process of finding
a derivative The process of finding
the antiderivative
Symbols:
Symbols:
)
(
'
,
'
, x
f
y
dx
dy
 dx
x
f )
(
Integral
Integrand
Tells us the
variable of
integration
 dx
x
f )
( is the indefinite integral of f(x) with respect to x.
Each function has more than one antiderivative (actually infinitely many)
2
3
2
3
2
3
2
3
3
58
3
4
3
6
3
x
x
x
x
x
x
x
x







Derivative of:
The
antiderivatives
vary by a
constant!
General Solution for an Indefinite Integral
C
x
F
dx
x
f 

 )
(
)
(
Where c is a constant
You will lose points if
you forget dx or + C!!!
Basic Integration Formulas
C
n
x
dx
x
n
n




 1
1
C
kx
dx
k 


C
a
ax
dx
ax 



cos
)
sin(
C
a
ax
dx
ax 


sin
)
cos(
C
a
ax
dx
ax 


tan
)
(
sec2
C
a
ax
dx
ax 



cot
)
(
csc2
C
a
ax
dx
ax
ax 


sec
)
tan
(sec
C
a
ax
dx
ax
ax 



csc
)
cot
(csc
Find:
 dx
x5
 dx
x
1
 xdx
2
sin
 dx
x
2
cos
C
x


6
6
C
x
C
x
dx
x 



 

2
2 2
1
2
1
C
x



2
2
cos
C
x
C
x




2
sin
2
2
1
2
sin
You can always check
your answer by
differentiating!
Basic Integration Rules

  dx
x
f
k
dx
x
kf )
(
)
(
  

 

 dx
x
g
dx
x
f
dx
x
g
x
f )
(
)
(
)
(
)
(
Evaluate:
 
 

 dx
x
x
x 4
6
5 2
3
 

 


 dx
dx
x
dx
x
dx
x 4
6
5 2
3
 

 


 dx
dx
x
dx
x
dx
x 4
6
5 2
3
C
x
C
x
C
x
C
x































 4
2
6
3
4
5
2
3
4
C
x
x
x
x




 4
3
3
4
5 2
3
4
C represents
any constant
Evaluate:
 dx
x
5 3

 5
3
x C
x


5
8
5
8
C
x 
 5
8
8
5
Evaluate:
 
  dx
x
x cos
3
sin
4
 

 xdx
xdx cos
3
sin
4
C
x
C
x 



 sin
3
cos
4
C
x
x 


 sin
3
cos
4
Evaluate:
 
  dx
x
2
2
3
 
 

 dx
x
x 4
2
6
9
C
x
x
x 



5
2
9
5
3
C
x
x
x



 9
2
5
3
5
Evaluate:
 dx
x
x
2
cos
sin
 
 dx
x
x
x cos
sin
cos
1
C
x
 sec
 
 xdx
x tan
sec
Particular Solutions
2
1
)
(
'
x
x
f  and F(1) = 0
dx
x
x
F 
 2
1
)
(
dx
x
x
F 

 2
)
(
C
x
x
F 



1
)
(
1
C
x
x
F 


1
)
(
0
1
1
)
1
( 


 C
F
1

C
1
1
)
( 


x
x
F

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Antiderivatives.ppt

  • 2. Discovery of Power Rule for Antiderivatives If f ‘ (x) = Then f(x) = If f ‘ (x) = Then f(x) = If f ‘ (x) = Then f(x) = If f ‘ (x) = Then f(x) = 3 2 9 4 2 3    x x x x x x x 3 3 2 3 4    2 3   x x x x x 2 2 3 3 2 2 2 3   5 4 3 2 3 2    x x x x x x x 5 2 2 3 5 3 2 2 3 5     5 3 4 2    x x x x x 5 2 3 3 4 2 3   
  • 4. Differentiation Integration The process of finding a derivative The process of finding the antiderivative Symbols: Symbols: ) ( ' , ' , x f y dx dy  dx x f ) ( Integral Integrand Tells us the variable of integration
  • 5.  dx x f ) ( is the indefinite integral of f(x) with respect to x. Each function has more than one antiderivative (actually infinitely many) 2 3 2 3 2 3 2 3 3 58 3 4 3 6 3 x x x x x x x x        Derivative of: The antiderivatives vary by a constant!
  • 6. General Solution for an Indefinite Integral C x F dx x f    ) ( ) ( Where c is a constant You will lose points if you forget dx or + C!!!
  • 7. Basic Integration Formulas C n x dx x n n      1 1 C kx dx k    C a ax dx ax     cos ) sin( C a ax dx ax    sin ) cos( C a ax dx ax    tan ) ( sec2 C a ax dx ax     cot ) ( csc2 C a ax dx ax ax    sec ) tan (sec C a ax dx ax ax     csc ) cot (csc
  • 8. Find:  dx x5  dx x 1  xdx 2 sin  dx x 2 cos C x   6 6 C x C x dx x        2 2 2 1 2 1 C x    2 2 cos C x C x     2 sin 2 2 1 2 sin You can always check your answer by differentiating!
  • 9. Basic Integration Rules    dx x f k dx x kf ) ( ) (         dx x g dx x f dx x g x f ) ( ) ( ) ( ) (
  • 10. Evaluate:       dx x x x 4 6 5 2 3         dx dx x dx x dx x 4 6 5 2 3         dx dx x dx x dx x 4 6 5 2 3 C x C x C x C x                                 4 2 6 3 4 5 2 3 4 C x x x x      4 3 3 4 5 2 3 4 C represents any constant
  • 11. Evaluate:  dx x 5 3   5 3 x C x   5 8 5 8 C x   5 8 8 5
  • 12. Evaluate:     dx x x cos 3 sin 4     xdx xdx cos 3 sin 4 C x C x      sin 3 cos 4 C x x     sin 3 cos 4
  • 13. Evaluate:     dx x 2 2 3       dx x x 4 2 6 9 C x x x     5 2 9 5 3 C x x x     9 2 5 3 5
  • 14. Evaluate:  dx x x 2 cos sin    dx x x x cos sin cos 1 C x  sec    xdx x tan sec
  • 15. Particular Solutions 2 1 ) ( ' x x f  and F(1) = 0 dx x x F   2 1 ) ( dx x x F    2 ) ( C x x F     1 ) ( 1 C x x F    1 ) ( 0 1 1 ) 1 (     C F 1  C 1 1 ) (    x x F